If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
y = (k*x^1)/3 // - (k*x^1)/3
y-((k*x^1)/3) = 0
y-((k*x)/3) = 0
y-1/3*k*x = 0 // - y
-1/3*k*x = -y // : -1/3*k
x = -y/(-1/3*k)
x = 3*k^-1*y
x = 3*k^-1*y
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